Chemistry, asked by sonabrainly, 1 month ago

the rate constant of a reaction is twice the temperature is 310 - 300 the activation energy
the rate constant is 6.93 x 10^-2 concentration of a is 2m how much time it takes to make b - 2m

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Answered by CHATURVEDIAYUSHI789
3

Answer:

1. First Order Reactions

Suppose we have a first order reaction of the form, B + . . . . → products. We can write the rate expression as rate = -d[B]/dt and the rate law as rate = k[B]b . Set the two equal to each other and integrate it as follows:

 \frac{d[B]}{dt} =  -k[B] \\  \\  \frac{d[B]}{[B]}  =  - k dt </p><p> \\ </p><p></p><p>1n \frac{[B]}{[B]°}  =  - kt \\  \\  [B]=[B]° e -kt .

1. First Order Reactions

The first order rate law is a very important rate law, radioactive decay and many chemical reactions follow this rate law and some of the language of kinetics comes from this law. The final Equation in the series above iis called an "exponential decay." This form appears in many places in nature. One of its consequences is that it gives rise to a concept called "half-life."

Answered by lp416867
0

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