Question

The rate constant of a zero order reaction is
0.2 mol dm Ph-1. If the concentration of the reactant
after 30 minutes is 0.05 mol dm3. Then its initial
concentration would be :-
(1) 6.05 mol dm3 (2) 0.15 mol dm3
(3) 0.25 mol dm3 (4) 4.00 mol dm-3

Answer 1

Answer:

integrated rate equation for zero order reaction is given by

k=((R initial)-(R final))÷time

where k=rate constant

R=concentration

according to problem

k=0.2

R final=0.05

t=30

so,we have

0.2=(R initial-0.05)÷30

on solving,we get R inital=6.05

Answer 2

Its initial  concentration would be [tex]6.05moldm^{-3} [/tex]

Explanation:

Zero order reaction : A reaction is said to be of zero order if the rate is independent of the concentration of the reactants, that means the rate is directly proportional to the zeroth power of the concentration of the reactants.

Expression for the zero order kinetics:

[tex][A]=-kt+[A]_o [/tex]

where [A] = concentration left after time t

[tex][A]_o [/tex] = initial concatenation

k= rate constant

t = time for reaction

[tex]0.05moldm^{-3}=-0.2\times 30+[A]_o [/tex]

[tex][A]_o=6.05moldm^{-3} [/tex]

Learn more about zero order kinetics:

https://brainly.in/question/6681095