Question

The rate equation of a chemical reaction ,2NO+O2------> 2NO2 is given as R=K[NO]^2[O2]. how will the rate of reaction change if the volume of the reaction of vessel reduced to 1/4of its original volume

Answer 1

Answer:

4 times  the rate of reaction will increase

Explanation:

as M = n/ V

M1 = n/ V/4

M1 = 4 * n/V

i.e., 4 * M

Hence proved.