The rate for the reaction
RCI + NaOH(aq) → ROH + NaCl is given by rate = K[RCI). The rate of reaction is
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4
Answer:
the order of rxn is 1 the rate is double if rcl conc. double and half is rcl conc. becomes half
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0
Answer:
Explanation:
the order of reaction is 1 and since NAOH is solvent it is present in excess and so it is not considered while writing the r.o.r so it will be halved on reducing the concentration of rcl to half
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