Chemistry, asked by kirti318, 7 months ago

The rate law for a reaction is found to be:
Rate=k[NO2^-][I^-][H^+]^2
How would the rate of reaction change when
(a) concentration of I^- is halved
(b) concentration of H^+ is doubled
(c) concentration of each of NO2^-, I^- and H^+ are tripled.


please guys answer this​

Answers

Answered by gokulmohanakrishnan
3

Answer:

The rate constant of a reaction does not depend upon concentrations of the reactants. Thus, it will remain the same. The rate constant of a reaction depends on temperature not on concentration.

Explanation:

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Answered by heyyall
1

Answer:

The rate constant of a reaction does not depend upon concentrations of the reactants. Thus, it will be the same.

Explanation:

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