Question

The rate law for areation between the substance A and B give by rate=k[A]^n[B]^m on doubling the concetration of A and leaving the consetration of B the ratio of the new rate to the earlirr rate of the racton would be?

Answer 1

Answer:

$2^n$

Step-by-step explanation:

The initial rate, $R_{i}$ is given by:

$R_{i} = k[A]^n[B]^m$ ...1

If the concentration of A is doubled, [A] becomes 2[A], and concentration of B is kept the same, so, the final rate, $R_{f}$ is given by:

$R_{f} = k(2[A])^n[B]^m$

$=> R_{f} = 2^n k[A]^n[B]^m$

From 1, we get:

$=> R_{f} = 2^n R_{i}$

So, $\frac{R_{f}}{R_{i}} = 2^n$