Chemistry, asked by lipuglenda19, 7 months ago

the rate law for the reaction 2a + b = c was found to be rate =k{A}{B}^2. If the concentration of B is tripled and the concentration of A is unchanged how many times will the reaction rate increase? show full working out.

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Answered by akanksha2614
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Chemistry

Chemical Kinetics

Factors Influencing Rate of a Reaction

The rate equation for the r...

CHEMISTRY

The rate equation for the reaction 2A+B→C is found to be : rate=k[A][B]. The correct statement in relation to this reaction is:

MEDIUM

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ANSWER

2A+B ⟶ C.

Rate = K[A][B]

∙ order of the given reaction = 2.

∴t

1/2

is not constant. It is constant only for a first order reaction.

∴ Unit of K for n

th

order reaction is M

(1−n)

time

−1

for a 2

nd

order reaction it is M

−1

S

−1

∴ As per rate law :

2

−1

dt

d[A]

=

dt

d[C]

∴ The rate of formation of C is half of the rate of disappearance of A.

∴ The rate constant is independent of the initial concentrations of the reactants. As k only changes when temperature chnages

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