Chemistry, asked by mohdumarfarooq41, 8 months ago

the rate law for the reaction aA+bBp is rate ,= k(a)(B) the rate of reactions double if​

Answers

Answered by sehajpalamit
2

Answer:

(a) aA+bB⇒ Product

Rate = K[A]

a

[B]

b

On doubling A

Rate →4 times

⇒a=2

On making concentration of B four times

Rate →2 times

b=1/2

∵ROR=

a

−1

dt

d[A]

=−

b

1

dt

d[B]

dt

−d[A]

=−4

dt

d[B]

this is the correct answer

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Answered by chandanahmchandana95
0

Answer:

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