The rate of a certain chemical reaction doubles for every 10 degree rise in temperature
Answers
Answered by
3
Rate at 50°C/(Rate at T1°C)
= (2)ΔT/T1
= (2)50/10
= 25
Answered by
2
Rate at 50°C/(Rate at T1°C)
= (2)ΔT/T1
= (2)50/10
= 25
= (2)ΔT/T1
= (2)50/10
= 25
Similar questions
Social Sciences,
7 months ago
History,
7 months ago
English,
7 months ago
Physics,
1 year ago
Math,
1 year ago
Social Sciences,
1 year ago