Chemistry, asked by viharikashankar, 1 year ago

the rate of a first order reaction is .06 mol/litre/min at 10 minutes and .03 mol/litre/min at 20 minutes after initiation. calculate the rate of reaction at 50 minutes after intiation

Answers

Answered by srikanth2716
0

Arrhenius Equation -

Arrhenius gave the quantitative dependence of rate constant on temperature by the Arrhenius equation.

- wherein

k = A e^{-E_{a}/RT}

In k=InA-\frac{E_{a}}{RT}

k = Rate constant

For a first-order reaction

K=\frac{2.303}{t_{2}-t_{1}}. \log\frac{[A]_{1}}{[A]_{2}}

\therefore K=\frac{2.303}{20-10}. \log\frac{(0.04)}{(0.03)}=0.0287 sec^{-1}

t_{\frac{1}{2}}=\frac{0.693}{K}= \frac{(0.693)}{(.0287)}=24.1 sec

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