Question

The rate of a reaction is doubled for every 10∘C rise in temperature . The increase in reaction rate as a result of temperature rise from 10∘C to 100∘C is

Answer 1

Answer:

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Answer 2

Final answer: The rate of reaction is increased by 512 times.

Given that: We are given the rate of a reaction is doubled for every 10°C rise in temperature.

To find: We have to find the increase in reaction rate as a result of temperature rises from 10°C to 100°C.

Explanation:

• In general, the rate of a reaction is proportional to some power of the molar concentration of each of the reactants.
• Generally, the rate of a reaction increase with an increase in the concentrations of the reactant.
• The rate of a reaction decrease with time because the concentrations of the reactant decrease with time.
• The given information is for every 10°C rise in temperature, the rate is doubled.

So, the temperature coefficient of that reaction = 2

• Let $r_{1}$ be the initial rate of reaction.

New rate $r_{2} = r_{1} \times 2^{(\frac{Temperature\ difference}{10})}$

• There is 9 times 10°C rise when the temperature rises to 100°C from 10°C.

That is the temperature difference $=100-10=$ $90\°C$

• Substitute this value into the new rate equation.

New rate $r_{2} = r_{1} \times 2^{(\frac{90}{10})}$

$= r_{1} \times 2^{9} \\\\ =512 \times r_{1}$

• Hence, the rate is increased by 512 times.

To know more about the concept please go through the links

https://brainly.in/question/5800435

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