Question

The rate of change of momentum of a body is 3 kg ms-2. What is the force acting on the body?

Answer 1

Answer:

the rate of change of momentum of a boby is 3

kg ms_ 2

Explanation:

the force acting on a boby is 6 force is acting

Answer 2

Answer:

★ Given :

• Momentum = Mass × Velocity
• P = 3kg × 2m/s

★ Answer :

Hence,

$\sf \longmapsto \: Mass = 3kg$

$\sf \longmapsto \: Velocity = 2m/s$

As we know that,

DeFiNiTiOn of Acceleration:-

• Acceleration is the defined as the rate of changr in velocity with respect to time.

$\sf \longmapsto \: V = 2m/s$

So, if we divide 2m/s with 3kg then we will have Acceleration:

$\sf \longmapsto \: 2m/s³$

As we also know that,

$\sf \longmapsto \: F = ma$

$\sf \longmapsto \: F = ( 3 × 2 ) Kg m/s³$

$\sf \longmapsto \: F = 6 kg m/s³$

$\sf \pink\mapsto \pink{\: F = 6 N}$

•°•The force acting on the body is 6 Newton.