The rate of chnge of current of 10 A/s in a cool produces an EMF of 5 V.then the self inductance of the coil in henry is?
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we knw that emf = L dI/dt
5 = L × 10
L = 1/2
HENCE self inductance is 0.5 H.
5 = L × 10
L = 1/2
HENCE self inductance is 0.5 H.
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