Question

The rate of constant for forward and backward reaction of hydrolysis of ester are 1.1*10^-2 and 1.5*10^-3 per minute respectively. Equilibrium constant for the reaction is

Answer 1

equilibrium constant will be 7.3

Answer 2

Answer:7.3

Explanation: Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

$A\rightleftharpoons B$

$K=\frac{[B]}{[A]}$

Rate of forward direction=$k_f[A]$

Rate of backward direction=$k_b[B]$

At equilibrium, Rate of forward direction = Rate of backward direction

thus $K=\frac{\text{Rate of forward direction}}{\text{Rate of backward direction}}=\frac{[B]}{[A]}$

$K=\frac{1.1\times 10^{-2}}{1.5\times 10^{-3}}=7.3$