Question

The rate of diffusion of helium and methane under identical conditions of temperature and pressure will be

Answer 1

Answer:2:1

Explanation: r1/r2=(m2/m1)^1/2

r = rate of diffusion

m = molecular weight

ATQ:

r1/r2 = (16/4)^1/2

= 4:1

MW of CH4 =16

MW of He2 =4