The rate of diffusion of methane at a given temperature is twice that of a gas X. The molecular weight of X is
(a) 64.0
(b) 32.0
(c) 4.0
(d) 8.0
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Formula : r1/r2 = (m2/m1) ^1/2
Given,
The rate of diffusion of methane is twice of a gas X
Let r1= rate of diffusion of methane = 2(r2)
r2 = rate od diffusion of gas X
M1=16
2(r2)/r2 = (m2/16)^1/2
Therefore M2 = 8
Hope this helps!!
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