Chemistry, asked by dhanush141, 1 year ago

the rate of diffusion of Methane at given temperature is twice that of gase x. the molecular weight of x is

Answers

Answered by anand782000
2
The rate of diffusion of two gases are compared as follow,, r1/2r1 = sqrt M2/M1
1/4 = 16/M1 => M2 = 64

So answer is 64.

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Answered by Yeshwanth1245
0

Answer:

The rate of diffusion of two gases are compared as follow,, r1/2r1 = sqrt M2/M1

1/4 = 16/M1 => M2 = 64

So answer is 64.

PLEASE MARK THIS AS A BRAINLIEST ...HAVE A GOOD DAY

Explanation:

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