Question

The rate of equation for the hydrolysis of an ester in the precence of naoh is,rate=k[ester][naoh].If the concntration of naoh is increased by 100 times than that of ester the order of reaction will be

Answer 1

Answer:

The rate expression is rate=k[ester][NaOH].

The rate expression is rate=k[ester][NaOH].Thus, the reaction is first order with respect to the concentrations of ester and NaOH. 

The rate expression is rate=k[ester][NaOH].Thus, the reaction is first order with respect to the concentrations of ester and NaOH. When the concentration of NaOH is 100 times the concentration of ester, it remains almost constant and the reaction becomes zero order with respect to [NaOH]. 

The rate expression is rate=k[ester][NaOH].Thus, the reaction is first order with respect to the concentrations of ester and NaOH. When the concentration of NaOH is 100 times the concentration of ester, it remains almost constant and the reaction becomes zero order with respect to [NaOH]. Hence, it is a pseudo-first-order reaction.

The rate expression is rate=k[ester][NaOH].Thus, the reaction is first order with respect to the concentrations of ester and NaOH. When the concentration of NaOH is 100 times the concentration of ester, it remains almost constant and the reaction becomes zero order with respect to [NaOH]. Hence, it is a pseudo-first-order reaction.rate=k[ester]1[NaOH]0.

Explanation:

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