Question

The rate of failure in an examination is 39.25%. Find the least number of total candidates appeared in the examination. (a) 500 (b) 400

Answer 1

Answer:

(b) 400

Step-by-step explanation:

39.25 / 100 * 400 = 39.25 * 4 = 157

39.25 / 100 * 500 = 39.25 * 5 = 196.25 (not possible)

Answer 2

The least number of total candidates appeared in the examination is 400

Solution:

Given that,

The rate of failure in an examination is 39.25%

Let "n" be the least number of total candidates appeared in the examination

Then,

Number of candidates failed = 39.25 % of n

Which means,

$\text{ Number of candidates failed } = 39.25 \% \times n \\\\\text{ Number of candidates failed } = \frac{39.25}{100} \times n$

We know, the number of candidates can not be a fraction

Consider, number of candidates failed = 157

Then,

$157 = \frac{39.25}{100} \times n \\\\n = 400$

Thus the minimum value of n for which this is a whole number is 400

Thus, the least number of total candidates appeared in the examination is 400

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