Question

The rate of flow of heat through
copper rod with temperature difference 30°C
is 1500 cal/s Find the thermal resistance of
copper rod.
plz answer fast ​

Answer 1

Answer:

The thermal resistance of the rod is 0.02 K s/Cal

Explanation:

As we know that rate of heat flow due to conduction mode of heat transfer is given as

$\frac{dQ}{dt} = \frac{(T_2 - T_1)}{R_{th}}$

here we know that

$\frac{dQ}{dt}$ = rate of heat transfer

$R_{th}$ = thermal resistance

so we have

$1500 = \frac{30}{R_{th}}$

$R_{th} = \frac{30}{1500}$

$R_{th} = 0.02 K s/Cal$

#Learn

Topic : Heat transfer

https://brainly.in/question/12602371

Answer 2

Explanation:

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