Question

The rate of flow of liquid in a tube of radius r, length l, whose ends are maintained at a pressure difference p is

Answer 1

The r be the radius,L be the length  and P is the pressure difference.Generally the Q is represented as rate of flow of liquid but here it is taken as V, Therefore V=  

ηl

πQpr  

4

 

​

 

As for now V=Q

Now using the Poiseuille equation for the rate of flow of liquid.

Which is V=πΔPr  

4

/8lη

Comparing with the above equation of V,  

So on comparing we get the value of Q=1/8

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