Question

The rate of formation of a dimer in a second 67.
order dimerisation reaction is 9.1 x 10-mol L-
s- at 0.01 mol L- monomer concentration.
What will be the rate constant for the reaction?​

Answer 1

Answer: rate = 9.1 x 10⁻⁶ mol litre /sec

Explanation:

For a second order reaction,

Rate of the reaction = Rate constant x [Reactant]²

We are told rate = 9.1 x 10⁻⁶ mol litre /sec

The Reactant here is the monomer.

[Reactant] = 0.01 mol/ litre

Rate constant =  

= 9.1 x 10⁻² mol⁻¹ sec⁻¹

The arrhenius equation is

k = A e⁻Eᵃ/RT

where k is rate constant.

R is universal gas constant.

Ea is activation energy.

A is the frequency factor.

T is the temperature