The rate of formation of a dimer in a second ord.
dimerisation reaction is 9.1 x 10 mol Lºs at 0.01 molt
monomer concentration. What will be the rate constant
for the reaction ?
(a) 9.1 x 10 L mol's' (b) 9.1 x 10 L mol's-1
(C)3 x 10^L mol's' (d) 27.3 x 10 ²L mol's
Answers
Answered by
1
Answer:
I think option (c) is right answer. ..
shravani8026:
no its a wrong ans actually ans is option a but i need the explanation of how to solve this sum
Answered by
2
Answer:Rate of the reaction = Rate constant x [Reactant]²
We are told rate = 9.1 x 10⁻⁶ mol litre /sec
The Reactant here is the monomer.
[Reactant] = 0.01 mol/ litre
Rate constant =
= 9.1 x 10⁻² mol⁻¹ sec⁻¹
The arrhenius equation is
k = A e ^
where k is rate constant.
R is universal gas constant.
Ea is activation energy.
A is the frequency factor.
T is the temperature.
Explanation:
but i still need a perfect ans coz i didnt get what u said
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