The rate of formation of a dimer in a second order reaction is 7.5×10^-1 mol L^-1 s^-1at 0.05 molL^-1 in monomers concentration. calculate the rate constant.
Answers
Answered by
1
Answer:
I am not fake but I am broken
Answered by
2
Answer:
Explanation:
Let us consider the dimerization of monomer M
2M->(M)2,rate=k(M)^ n
Given,n=2and(M)=0.05 mol L
Rate=7.5x10^-3 mol L-¹ s-¹
K=rate/(M)^n
=7.5x10^-3/(0.05)²
=3 mol-¹ L
Similar questions