Question

The rate of formation of a dimer in a second order reaction is 7.5×10^-1 mol L^-1 s^-1at 0.05 molL^-1 in monomers concentration. calculate the rate constant.​

Answer 1

Answer:

I am not fake but I am broken

Answer 2

Answer:

Explanation:

Let us consider the dimerization of monomer M

2M->(M)2,rate=k(M)^ n

Given,n=2and(M)=0.05 mol L

Rate=7.5x10^-3 mol L-¹ s-¹

K=rate/(M)^n

=7.5x10^-3/(0.05)²

=3 mol-¹ L