Question

the rate of formation of SO3 in the reaction 2SO2+O2-->2SO3 is 100g/min.rate of disappearance of O2

Answer 1

Answer: 50 g/min

Explanation: Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction: $2SO_2+O_2\rightarrow 2SO_3$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

$Rate=-\frac{1d[SO_2]}{2dt}=-\frac{d[O_2]}{dt}=+\frac{1d[SO_3]}{2dt}$

Given: $\frac{d[SO_3]}{dt}]$= 100 g/min

$-\frac{d[O_2]}{dt}=+\frac{1d[SO_3]}{2dt}$

$-\frac{d[O_2]}{dt}=+\frac{1}{2}\times 100g/min$

$-\frac{d[O_2]}{dt}=50g/min$

Thus rate of disappearance of oxygen is 50 g/min.

Answer 2

Answer:

Well answere is 20 g/min

Explanation:

Key step to solve this question is

Covert the given mass of SO3 into moles

And the remaining steps are given below in pic