Math, asked by Satheesh9047, 2 months ago

the rate of interest at which rs 100 become rs 200 in 10 years​

Answers

Answered by tejalingle81
1

Answer:

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Answered by BrainlyPhantom
2

Solution:

Principal Amount (P) = Rs.100

Rate of Interest (R) = Unknown

Time period (n) = 10 years

Simple Interest (S.I) = Rs.200

In order to find the rate of interest, we must use the Simple interest formula which is given below:

\sf{\implies\:S.I=\dfrac{P\times\:R\times\:T}{100}}

Substituting the values into the equation:

\sf{\longrightarrow\:200=\dfrac{100\times\:R\times10}{100}}

\sf{\longrightarrow\:200=\dfrac{100\times\:R}{10}}

\sf{\longrightarrow\:200=10R}

\sf{\longrightarrow\:R=\dfrac{200}{10}}

\sf{\longrightarrow\:R=20\%}

The rate of interest at which Rs.100 must be deposited to get an interest amount of Rs.200 is 20%.

Simple interest formulae:

\sf{\implies\:S.I=\dfrac{P\times\:R\times\:T}{100}}

To find the simple interest the product of the principal amount, rate of interest and time must be divided by 100.

\sf{\implies\:A=P+I}

In order to find the total amount, we must add the Principal amount and the interest amount.

Note:-

In order to find individual values like P, R, T, A etc. when other values are given, these formulae can be implemented.

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