Math, asked by yazz38, 1 month ago

The rate of popcorn was reduced by 20%, and now a customer can buy 15 kg more popcorn for Rs 300 than usual. The difference of actual and changed price per kg is?​

Answers

Answered by guptasachi05
2

Answer:

I don't know this answer

Answered by Anonymous
2

Given,

The rate of popcorn is reduced by 20%

Now, a customer can buy 15 kg more popcorn for Rs 300 than usual.

To find,

The difference of actual and changed price per kg.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Let, the initial price per kg = Rs. x

Reduced price per kg = x - (x × 20/100) = x - x/5 = Rs. 4x/5

In the initial price,

Rs. x = 1 kg popcorn

Rs. 1 = 1/x kg popcorn

Rs. 300 = 300/x kg popcorn

In the reduced price,

Rs. 4x/5 = 1 kg popcorn

Rs. 1 = 5/4x kg popcorn

Rs. 300 = 1500/4x = 375/x kg popcorn

According to the data mentioned in the question,

375/x - 300/x = 15

375-300/x = 15

75/x = 15

15x = 75

x = 5

Initial price = Rs. 5 per kg

Reduced price = 5 - (5×20/100) = 5-1 = Rs. 4 per kg

Difference of price per kg = 5-4 = Re. 1

Hence, the difference of actual and changed price per kg is Re. 1

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