The rate of reaction between two reactant a and b decreases by a factor of 4 if the concentration of the reactant b is doubled. The order of reaction with respect to the reactant bis?
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xA + yB ----------> Product
Rate= k[A]^x.[B]^y .........(i)
When conc. of B is doubled,
Rate/4 = k[A]^x.[2B]^y...........(ii)
Equation (i)/(ii)
4=1/2^y
⇒2^y = 1/2²
⇒y=-2 with respect to B
Rate= k[A]^x.[B]^y .........(i)
When conc. of B is doubled,
Rate/4 = k[A]^x.[2B]^y...........(ii)
Equation (i)/(ii)
4=1/2^y
⇒2^y = 1/2²
⇒y=-2 with respect to B
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