Chemistry, asked by prabir2942, 1 year ago

The rate of reaction x to y becomes 8 times when the concentration of the reactant x is doubled. write the rate law of the reaction ?

Answers

Answered by rare21
4
the rate law is k(x)^2(y)^1
Answered by ua57116
4

Answer:

The rate law is

dx/dt= k(x)^2(y)^1

Third Order Of Reaction

Explanation:

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