the rate of the reaction doubles when the concentration of the reactant is increased four times .the order of the reaction is 1)half 2)second 3)first 4) zero
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Answer:
The expression for the rate of the reaction is r=k[A]
n
......(1)
When the concentration of A is doubled, the rate increases 4 times.
r
′
=4r=([2A]
n
)......(2)
Dividing (2) by (1), we get
r
4r
=
k[A]
n
([2A]
n
)
n=2.
When the concentration of A is tripled, the rate increases 9 times.
r
′
=9r=k([3A]
n
)......(1)
Dividing (3) by (1), we get
r
9r
=
k[A]
n
k([3A]
n
)
n=2
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