Physics, asked by untpjpt, 1 day ago

The rating of an electric bulb is 240v and 100 wath. What is the resistance of the filament of the bulb? How much amount of maximum current can flow through this Bulb?

Answers

Answered by bhanuprakashmuddala

1

Explanation:

P=100W

V=240v

P=VI

I=100/240=5/12=0.41A

P=V²/R

R=V²/P=(240*240)/100=576 ohm

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