The rating of an electric heater is 1100W;220V.Calculate its resistance when it operates at 220V.Also calculate the energy consumed in kWh in the month of november if the heater is used daily for four hours at the rated voltage.
Answers
The resistance is 44 ohms And the energy consumed is 4.4 Kilowatt hours.
Explanation:
Given, Power = 1100 watt Voltage = 220 Volts And we know that, P = V square / R. 1100 = (220) square / R. R = 220 X 220 / 1100 = 44 ohms. And energy consumed = Power X time. 1100 Watts X 4 hours = 1.1 kilowatt X 4. =4.4 kilowatt hours. (Got the answer)
The resistance of the heater is 44 Ω and the energy consumed in November in kWh is 132 kWh.
Given,
The rating of an electric heater is 1100W;220V.
To Find,
The resistance when it operates at 220 V and the energy consumed in kWh in November if the heater is used daily for four hours.
Solution,
The formula for calculating the power of the heater is
P = V²/R
1100 = (220)(220)/R
R = 220*220/1100
R = 22*22/11 = 44 Ω
Now,
The formula for calculating the energy is
Energy = Power*time
Now,
Time = 30*4 = 120 hours { there are 30 days in November and each day the heater is used for 4 hours.}
Power = 1100W = 1100/1000 = 1.1 kW
Energy = 1.1*120 = 132 kWh.
Hence, the resistance of the heater is 44 Ω and the energy consumed in November in kWh is 132 kWh.
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