Math, asked by SUDHANSHU006, 1 year ago

the ratio between the ages of A and B is 7:9. 9 years ago, their ages were in the ratio of 2:3. find their present ages?

Answers

Answered by ishwarsinghdhaliwal
36
Hope it helps.......................
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Answered by Golda
22
Solution :-

Ratio of the ages of A and B = 7 : 9

Let the present ages of A and B be 7x and 9x

9 years ago, the ratio of the ages of A and B = 2 : 3

9 years ago, the age of A = (7x - 9) years

9 years ago, the age of B = (9x - 9) years

Now, according to the question.

⇒ (7x - 9)/(9x - 9) = 2/3

⇒ 21x - 27 = 18x - 18

⇒ 21x - 18x = - 18 + 27

⇒ 3x = 9

⇒ x = 9/3

⇒ x = 3

Now, substituting the value of x = 3

Present age of A = 7*3 = 

= 21 years

Present age of B = 9*3

= 27 years.

So, the present age of A is 21 years and the present age of B is 27 years.

Answer.
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