the ratio between the ages of A and B is 7:9. 9 years ago, their ages were in the ratio of 2:3. find their present ages?
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Solution :-
Ratio of the ages of A and B = 7 : 9
Let the present ages of A and B be 7x and 9x
9 years ago, the ratio of the ages of A and B = 2 : 3
9 years ago, the age of A = (7x - 9) years
9 years ago, the age of B = (9x - 9) years
Now, according to the question.
⇒ (7x - 9)/(9x - 9) = 2/3
⇒ 21x - 27 = 18x - 18
⇒ 21x - 18x = - 18 + 27
⇒ 3x = 9
⇒ x = 9/3
⇒ x = 3
Now, substituting the value of x = 3
Present age of A = 7*3 =
= 21 years
Present age of B = 9*3
= 27 years.
So, the present age of A is 21 years and the present age of B is 27 years.
Answer.
Ratio of the ages of A and B = 7 : 9
Let the present ages of A and B be 7x and 9x
9 years ago, the ratio of the ages of A and B = 2 : 3
9 years ago, the age of A = (7x - 9) years
9 years ago, the age of B = (9x - 9) years
Now, according to the question.
⇒ (7x - 9)/(9x - 9) = 2/3
⇒ 21x - 27 = 18x - 18
⇒ 21x - 18x = - 18 + 27
⇒ 3x = 9
⇒ x = 9/3
⇒ x = 3
Now, substituting the value of x = 3
Present age of A = 7*3 =
= 21 years
Present age of B = 9*3
= 27 years.
So, the present age of A is 21 years and the present age of B is 27 years.
Answer.
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