Question

The ratio between the ages of Meena and Sangeeta is 7:4 and difference between their ages is 18 years. The ratio between the ages after a years will be? 1. 11:17 2. 11:9 3. 11:8 4. 9:1

Answer 1

GIVEN :–

• The ratio between the ages of Meena and Sangeeta is 7:4 .

• Difference between their ages is 18 years.

TO FIND :–

• The ratio between the ages after a years will be ?

SOLUTION :–

• Let the age of Meena = x

• And the age of Sangeeta = y

▪︎ According to the first condition –

$\\ \implies { \bold{ \dfrac{x}{y} = \dfrac{7}{4}}}$

$\\ \implies { \bold{ x = \dfrac{7y}{4} \: \: \: \: \: - - - eq.(1)}}$

• According to the second condition –

$\\ \implies { \bold{x - y = 18}}$

• Now Using eq.(1) –

$\\ \implies { \bold{ \dfrac{7y}{4} - y = 18}}$

$\\ \implies { \bold{ \dfrac{7y - 4y}{4} = 18}}$

$\\ \implies { \bold{ \dfrac{3y}{4} = 18}}$

$\\ \implies \large{ \boxed{ \bold{ y = 24}}}$

• Put the value of 'y' in eq.(1) –

$\\ \implies { \bold{ x = \dfrac{7(24)}{4} }}$

$\\ \implies { \bold{ x = 7 \times 6}}$

$\\ \implies \large{ \boxed { \bold{ x = 42}}}$

▪︎ So that –

• Age of Meena = 42 year

• Age of Sangeeta = 24 year

▪︎ Now Let's find –

$\\ \implies { \bold{Ratio \: \: after \: \: a \: \: year = \dfrac{42 + 1}{24 + 1} }}$

$\\ \implies { \bold{Ratio \: \: after \: \: a \: \: year = \dfrac{43}{25} }}$

Answer 2

Step-by-step explanation:

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Given,.

Ratio between the ages of Meena and Sangeeta is 7:4.

Let 'X' be the age of Meena and 'Y' be the age of Sangeeta.

X:Y = 7:4

X. 7

___ = ____

Y. 4

X= 7×Y÷ 4 ---->eq 1

And Also given that,.

difference between their ages is 18 years

So let it be ,

X-Y=18 ----> eq 2

Replacing eq 1 in eq 2

7Y

___ - Y= 18

4

7Y-4Y

_____ = 18

4

3Y

__ = 18

4

3Y =18×4

3Y=72

Y= 72

__

3

Y=24

So, Sangeeta age is 24 years .

Now from

X-Y=18

X-24=18

X= 24+18

X= 42

Hope it will help you

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