Question

the ratio between the molecules in equal masses of ch4 and so2 is

Answer 1

Here
Mole = weight / molecular weight

Mole of methane = mass / 16
And
Mole of S02 = mass/64

Therefore the ratio = 64/16 =4

..: the ratio between the molecules in equal masses of CH4 And So2 is4

Answer 2

Answer: 4

Explanation: Let the mass of  $CH_4$ and $SO_2$ is x grams.

Molar mass of $CH_4$ = 16 g

Molar mass of $SO_2$ = 64 g

According to Avogadro's law, Molar mass of every substance contains Avogadro's number of particles.

16 g of  $CH_4$ contains=$6.023\times 10^{23}$  molecules of $CH_4$

x g of  $CH_4$ contains=$\frac{6.023\times 10^{23}}{16}\times 1=0.376\times 10^{23}$  molecules of $CH_4$

64 g of  $SO_2$ contains=$6.023\times 10^{23}$  molecules of $SO_2$.

x g of  $SO_2$ contains=$\frac{6.023\times 10^{23}}{64}\times 1=0.094\times 10^{23}$  molecules of $SO_2$

The ratio between the molecules in x g of $CH_4$and $SO_2$ is= $\frac{0.376\times 10^{23}}{0.094\times 10^{23}}=4$