The ratio between the no. Of sides of 2 regular polygon is 1:2 and ratio between interior angles is 2:3. find sides of polygon?
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Given ratio of numbers of sides of two regular polygin is 1:2.
Let numbers of sdes be a,2a.
Interior angle of regular polygon with a sides=180°-360°/a
Interior angle of regular polygon with 2a sides=180°-360°/2a
Acording to question..
((180°-360°/a))/((180°-180°/a))=2/3
(a-2)/(a-1)=2/3
3a-6=2a-2
a=4
Hence required regular polygons are square and octagon.
Therefore, the correct answer is square and octagon.
Hope that helped you.
If yes then please don't forget to mark my answer as the brainliest answer.
Thanks.
Let numbers of sdes be a,2a.
Interior angle of regular polygon with a sides=180°-360°/a
Interior angle of regular polygon with 2a sides=180°-360°/2a
Acording to question..
((180°-360°/a))/((180°-180°/a))=2/3
(a-2)/(a-1)=2/3
3a-6=2a-2
a=4
Hence required regular polygons are square and octagon.
Therefore, the correct answer is square and octagon.
Hope that helped you.
If yes then please don't forget to mark my answer as the brainliest answer.
Thanks.
Answered by
0
u type wrong ...i have tried 2-3 times ...after that i found mistake that ratio of exterior to interior is given ... please mark it as a brainliest answer
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