Question

The ratio between the present ages of A
and B is 3:5 respectively. If the
difference between B's present age and A's
age after 4 years is 2, what is the total of
A's and B's present age (in years)?​

Answer 1

AnswEr :

Let the Present Age of A be 3n and, Present Age of B be 5n.

• AFTER⠀4⠀YEARS :

◗ A = (3n + 4) yrs

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• According to the Question Now :

↠ B's Present – A's after 4 years = 2

↠ 5n – (3n + 4) = 2

↠ 5n – 3n – 4 = 2

↠ 2n = 2 + 4

↠ 2n = 6

• Dividing both term by 2

↠ n = 3

__________________

• Total Present Age of A and B :

↠ Sum = A + B

↠ Sum = 3n + 5n

↠ Sum = 8n

• putting the vale of n

↠ Sum = 8( 3 )

↠ Sum = 24 years

∴ Sum of Present Age of A & B is 24 years.

Answer 2

Question :-- The ratio between the present ages of A

and B is 3:5 respectively. If the difference between B's present age and A's age after 4 years is 2, what is the total of A's and B's present age (in years) ?

Solution :--

Given ratio of A and B present age is = 3 : 5 .

Lets assume that, present age of A and B is = 3x and 5x respectively .

So,

→ A after 4 years will be = (3x+4) years old.

Now, it has been said that, the difference between B's present age and A's age after 4 years is 2.

So,

→ B's Present - (A after 4 yrs ) = 2

→ 5x - (3x + 4) = 2

→ 5x - 3x - 4 = 2

→ 2x = 2 + 4

→ 2x = 6

→ x = 3 .

So, A present Age = 3x = 3*3 = 9 years.

→ B present age = 5x = 5*3 = 15 years.

Hence, Total of A's and B's present age = 9+15 = 24 years.