Math, asked by abdulkhanabdul1058, 10 months ago

The ratio between the present ages of A and B is 5:3 respectively. The ratio between A's age 4 years ago and B's age 4 years hence is 1:1. What is the ratio between A's age 4 years hence and B's age 4 years ago?

Answers

Answered by arun135094
21

Answer:

3:1

Step-by-step explanation:

Given, A's ratio and B's ratio = 5:3

As per the Ratio between A's age four years ago and B's age four years hence = 1:1

5x-4 : 3x+4 = 1:1

5x-4/3x+4 =1

5x-4 = 3x+4

5x-3x = 4+4

2x = 8

x = 4

A's present age = 5x = 5×4 = 20 years

B's present age = 3x = 3×4 = 12 years

Now the ratio between A's age 4 years hence and B's age 4 years ago

5x+4 : 3x-4 = 20+4 : 12-4

= 24 : 8

= 3 : 1

Answered by vinitahansda
5

Answer:

3:1

Step-by-step explanation:

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