Math, asked by richardruban232, 5 hours ago

The ratio between the present ages of Amon and Chan is 3: 4. The ratio of Bevan's age after 5 years to Chan's age 1 year ago is 4:3 and four times the difference in ages of Chan and Amon is one more than the age of Bevan. Find the average of the present ages of Amon and Chan. Select one.​

Answers

Answered by Biotechnologist22
0

Answer:   14

Step-by-step explanation:

Let Amon's age =  A

Let Bevan's age = B

Let Chan's age = C

Given :

A/C = 3/4               Equation 1

B+5 / C-1 = 4/3      Equation 2

4× (C-A) = B+1       Equation 3

From equations 1, 2 & 3

A = 12

B =  15

C = 16

Average of present ages of Amon & Chan = A+C / 2

                                                                            = 12+16 / 2
                                                                            = 28 / 2

                                                                            = 14

Similar questions