Question

The ratio between the present ages of Soni and her husband is 4:7 respectively. Also, her husband is 18 years older than her. What is the present age of Soni’s brother, who is half the present age of Soni’s husband?

Answer 1

Let, the present ages of Soni and her husband be 4x and 7x

ATP

7x = 18+4x

=) 7x-4x = 18

=) 3x = 18

=) x = 18/3 = 6

Soni's age = (4×6) = 24yrs

Soni's husband's age = (7×6) = 42yrs

Present age of Soni's brother

= (½×42) yrs

= 21yrs

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Answer 2

Answer:

The age of Soni is 24 years.

The age of Soni's husband is 42 years.

The age of Soni’s brother is 21 years.

Step-by-step explanation:

Step 1: Let the age of Soni is 4x and

             Let the age of her husband is 7x.

Given Her husband is 18 years older than her.

So, 7x=4x+18

Solve the equation above.

7x-4x=18

3x=18

x=$\frac{18}{3}$

x=6

Step 2: To find the Soni's age substitute the value of x in 4x.

4x=4×6

4x=24

Soni's age is 24 years.

Step 3: To find Soni's husband's age substitute the value of x in 7x.

7x=7×6

7x=42

Soni's husband's age is 42 years.

Step 4: Find Soni’s brother's age, who is half the present age of Soni’s husband.

42×$\frac{1}{2}$=21

The age of Soni’s brother is 21 years.