Question

The ratio between the radius of the base and the height of a cylindrical tank is 3:4. If its volume is 4851 m3, then the curved surface area of the cylinder is equal to​

Answer 1

Answer:

Step-by-step explanation:

Answer

Let r=2x and h=3x.

V=πr  

2

h

⟹  

7

22

​  

×(4x  

2

)(3x)=1617

⟹x  

3

=42.875

⟹x=3.5cm

Hence, r=7cm and h=10.5cm

Total surface area=2πrh+2πr  

2

=2πr(r+h)

=2×  

7

22

​  

×7(17.5)

=770cm  

2

 

Answer 2

Answer:

Here is the answer for ur question