Question

The ratio between the school ages of Pratosh and Satheesh is 5:6 respectively. If the ratio between the one-third age of Pratosh and half of Satheesh's age of 5:9, then what is the school age of Satheesh?​

Answer 1

Answer:

pratosh: Satheesh=5:6

let pratosh age=5x

sahteesh age=6x

according to question-

5x/3:6x/2=5:9

x=3

hence school age of Satheesh=6×3=18years

Answer 2

Answer:

We should find the school age of Satheesh using the given ratios.

Final Answer:  Cannot be determined

Step-by-step explanation:

From the given question,

• The ratio between the school ages of Pratosh and Satheesh is 5:6.

It shuld be written as,

              The school age of Pratosh    $=5x$

              The school age of Satheesh $=6x$

• The ratio between the one-third age of Pratosh and half of Satheesh's age of 5:9.It should be written as,

                    One-third age of Pratosh  $=\frac{1}{3}*5x$

                     Half of Satheesh's age     $=\frac{1}{2}*6x$

                                                        $\frac{\frac{1}{3}*5x}{\frac{1}{2}*6x} =\frac{5}{9}$

• First cancel the x in the numerator and denominator.

                                                         $\frac{\frac{1}{3}*5}{\frac{1}{2}*6} =\frac{5}{9}$

• Cancel 6 and 2 in the denominator. That is,

                                                        $\frac{\frac{1}{3}*5}{3} =\frac{5}{9}$

• The above equation can be written as,

                                                      $\frac{5}{3}*\frac{1}{3} =\frac{5}{9}$

                                                            $\frac{5}{9} =\frac{5}{9}$

• So that we can't find the school age of Satheesh.
• Final Answer:  Cannot be determined.