Physics, asked by student9479, 8 months ago

The ratio between the sine of angle of incidence in water to the sine of angle of incidence in air is 0.75, Calculate refractive index of water in respect with air.​

Answers

Answered by vermarachit34
10

Answer:

1.33

Explanation:

Refractive index of water with respect to air that means a|u|g= 3x10^8/2.25×10^8

=4/3

=1.33

Answered by dualadmire
2

The refractive index of water with respect to air is 1.333.

Given: The ratio between the sine of the angle of incidence in water to the sine of the angle of incidence in the air is 0.75

To Find: The refractive index of water with respect to air.

Solution:

  • The ratio between the speed of light in medium to speed in a vacuum is the refractive index.
  • Refractive index can be found using the formulas,

Refractive Index (RI) = sine of the angle of incidence/ sine of the angle of refraction.

Refractive Index (RI) = speed of light in air/ speed of light in the medium.

We know that the refractive index of air with respect to water is,

aμw = the sine of the angle of incidence in water/sine of the angle of incidence in air

       = 0.75                             [given]

We need to find the refractive index of water with respect to air,

So wμa = 1 / aμw

            = 1 / 0.75

            =  1.333

Hence, the refractive index of water with respect to air is 1.333.

#SPJ2

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