Question

The ratio between two consecutive spindle speeds for a six-speed drilling machine using drills
of diameter 6.25 to 25 mm size and at a cutting velocity of 18 m/min is?​

Answer 1

Answer:

1.32 pls follow me

Explanation:

V=π*D*N/1000.

So, N1D1=N2D2.

N1/N2=D1/D2.

=25/6.25.

=4.

NOW,

(Nmax/Nmin)^1/(6-1).

=4^(1/5),

=1.319,

~1.32.