Question

The ratio (by mass) of different atoms present in a molecule of ethyne is​

Answer 1

mass of C in C²H² =24

mass of H in C²H²=2

RATIO =24:2=12:1

Answer 2

Given:

the element mentioned in the question is ethyne.

To find:

here, we need to find the ratio (by mass) of individual atoms present in the molecule of Ethyne.

solution:

• The molecular formula of Ethyne is  C2H2.

• Elements present in Ethyne(C2H2) are Carbon (C) and Hydrogen (H).

Mass of individual atoms present in a ethyne will be:

• Mass of one carbon atom = 12u

        2 x carbon atoms(C2)  = 2 x 12 = 24

• Mass of one hydrogen atom = 1u

        2 x Hydrogen atom(H2) = 2 x 1 = 2

Ratio by mass of different atoms present in a compound will be:

•  2 x carbon atoms(C2) : 2 x hydrogen atom(H2)

        =                          2 x 12 : 2 x 1

        =                                24 : 2

        =                                12 : 1

hence, The ratio (by mass) of different atoms present in a molecule of ethyne is​ 12:1