Question

The ratio in the ages of A,B,and,C six years before was 2:3:5. If the sum of their present ages is 168.Find their ages​

Answer 1

Answer:

A,B,C are six year before was 2:3:5.

let's the age will be X

and sum of their present age is 168.

then,

2x+3x+5x=168

10x=168x

x=168/10

x=16.8

then the 2:3:5 are become

2x =2*16.8=33.6

3x=3*16.8=50.4

5x=5*16.8=84

These are the ages of A,B , and,C.

hope it help to you

Answer 2

Given:

The ratio in the ages of A,B,and,C six years before was 2:3:5.

Sum of their present ages is 168.

To Find:

Find their ages

Solution:

Let the ages be A, B, C

Ratio of ages before 6 years,

A:B:C = 2:3:5

Let A = 2x

     B = 3x

     C = 5x

Current ages will be 2x+6, 3x+6 and 5x+6 respectively

So,

Sum of current ages = 2x+6+3x+6+5x+6 = 168

                                                     10x + 18 = 168

                                                            10x = 150

                                                               x = 15

Their current age is

A = 2x+6 = 2*15+6 = 36

B = 3x+6 = 3*15+6 = 51

C = 5x +6 = 5*15+6 = 81

Hence, ages of A,B and C are 36 yrs, 51 yrs and 81 yrs respectively.