Question

the ratio in the ages of A,B and C six years before was 2:3:5. if the sum of their present ages is 168, find their ages.​

Answer 1

$\large\mathfrak \pink{Solution:-}$

$\underline \mathbb{GIVEN:-}$

★The ratio of the ages of A , B and C before six years was 2 : 3 : 5 .

★Sum of their present ages is 168 years.

$\underline \mathbb{TO \: FIND:-}$

★Their ages.

$\underline \mathbb{ASSUMPTION:-}$

Let, The age of A , B and C before six years be 2x , 3x and 5x

So, their present ages means their ages after six years will be (2x+6) , (3x+6) , (5x+6)

$\underline \mathbb{BY \: THE \: PROBLEM:-}$

(2x+6) + (3x+6) + (5x+6) = 168

or, 10x + 18 = 168

or, 10x = 168 - 18

or, 10x = 150

or, x = $\cancel{\frac{150}{10}}$

or, x = 15

$\underline \mathbb{ANSWER:-}$

Present age of A = (2x+6) = 15 × 2 + 6 = 36 years

Present age of B = (3x+6) = 15 × 3 + 6 = 51 years

Present age of C = (5x+6) = 15 × 5 + 6 = 81 years