Question

The ratio in the ages of A, B, C six years before was2:3:5.If the sum of their present ages is 168 , Find their ages.

Answer 1

Let the ages be A, B, C

Ratio of ages before 6 years

A:B:C = 2:3:5

A = 2x

B = 3x

C = 5x

Current ages

2x+6,3x+6,5x+6

Sum of ages

2x+6+3x+6+5x+6 =168

10x+18=168

10x = 150

x = 15

Their ages is

A = 2x+6 = 2*15+6 = 36

B = 3x+6 = 3*15+6 = 51

C = 5x +6 = 5*15+6 = 81

Answer 2

Given,

• The ratio in the ages of A, B, and C is six years before is 2:3:5.
• The sum of the present ages of A, B, and C is 168.

To find,

• We have to find the ages of A, B, and C.

Solution,

We can simply find the ages of A, B, and C by using the given conditions.

Let the constant of the ratio be 'x'

then the ages of A, B, and C six years before are 2x,3x, and 5x.

Age of A after 6 years = 2x +6

Age of B after 6 years = 3x+6

Age of C after 6 years = 5x+6

Now, the sum of the present ages of A, B, and C is 168, then

    2x+3x+5x + 18 = 168

              10x  + 18 = 168

                         10x = 168-18

                         10x = 150

                             x = 150/10

                            x = 15

Present age of A = 2(15) +6

                             = 36 Years

Present age of B = 3(15) +6

                              = 51 years

Present age of C = 5(15) +6

                             = 81 years

Hence, the ratio in the ages of A, B, and C six years before was2:3:5. If the sum of their present ages is 168 , then the ages of A, B, and C are 36, 51, and 81 years respectively.