the ratio in which c(-1,6) divides A(-3,10) and B(6,-8)
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5
Answer:
2 : 7
Step-by-step explanation:
Let the ratio in which C(- 1, 6) divided line segment containing points A(- 3, 10) and B(6, - 8) be k : 1.
So, m₁ = k, m₂ = 1
Also, x₁ = - 3, y₁ = 10
x₂ = 6, y₂ = - 8
& x = - 1, y = 6
Using section formula, we get
→ x = (m₁x₂ + m₂x₁) / (m₁ + m₂)
→ - 1 = [(k)(6) + (1)(- 3)] / (k + 1)
→ - 1 = (6k - 3) / (k + 1)
→ - 1(k + 1) = 6k - 3
→ - k - 1 = 6k - 3
→ 6k + k = - 1 + 3
→ 7k = 2
→ k = 2/7
We assume earlier that the ratio is :
→ k : 1
→ k / 1
→ (2/7) / 1
→ 2 / 7
Hence, the ratio is 2 : 7.
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