Question

The ratio in which C (-1,6) divides A( -3, 10) and B(6,-8) is :

Answer 1

Answer:

Answer:2:7 internally

Step-by-step explanation:

Let the ratio be k:1 in which C divides the line AB.

It is given that C divides AB, so by using section formula

(-1, 6) = [(6k-3)/(k+1)] , [(-8k+10)/(k+1)]

Then, we separate the absicca and ordinate.

- 1=(6k-3)/(k+1) 6=(-8k+10)/(k+1)

-k-1=6k-3 6k+6=-8k+10

Then, we have to solve both the equations and then check whether the value of k is internally or externally.

k=2/7 k=2/7

As the value of k is same in both equations and also it is intersects internally.

Therefore, the value of the ratio is 2:7 internally.

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